By Stephen Mann

ISBN-10: 1598291165

ISBN-13: 9781598291162

During this lecture, we research Bézier and B-spline curves and surfaces, mathematical representations for free-form curves and surfaces which are universal in CAD structures and are used to layout airplane and vehicles, in addition to in modeling applications utilized by the pc animation undefined. Bézier/B-splines symbolize polynomials and piecewise polynomials in a geometrical demeanour utilizing units of keep watch over issues that outline the form of the outside. the first research software utilized in this lecture is blossoming, which supplies a sublime labeling of the regulate issues that enables us to investigate their homes geometrically. Blossoming is used to discover either Bézier and B-spline curves, and particularly to enquire continuity homes, swap of foundation algorithms, ahead differencing, B-spline knot multiplicity, and knot insertion algorithms. We additionally examine triangle diagrams (which are heavily regarding blossoming), direct manipulation of B-spline curves, NURBS curves, and triangular and tensor product surfaces.

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**Additional resources for A blossoming development of splines**

**Example text**

While there are other factors that might seem to favor de Casteljau’s algorithm, they are of lessor importance. For example, in addition to evaluating for position, we also get the derivatives of the polynomial when we use de Castlejau’s algorithm. This is not a major consideration, since both Horner’s rule and forward differencing can also give you the derivatives at a lower cost than de Castlejau’s algorithm. Another observation is that de Castlejau’s algorithm is numerically more stable stable than is forward differencing.

0) k! n− j −k n− j ¯ . . , 0¯ , δ, . . , δ )u k f ∗ (0, k k=0 k=0 ( j +k) = F (u) n− j ¯ . . , 0¯ , δ, . . , δ )u k f ∗ (δ, . . 4. ) = Note that this is multilinear: each term has either u i or wi as a linear term. Thus, α f ∗ (u, ¯ . . ). f ∗ (α u, Now let us evaluate our multilinear blossom at f ∗ (u¯ 1 , u¯ 2 , δ). Then F(u) = 3u 3 + 2u 2 + 6u + 1 f ∗ (u¯ 1 , u¯ 2 , u¯ 3 ) = 3u 1 u 2 u 3 + 2(u 1 u 2 w3 + u 2 u 3 w1 + u 3 u 1 w2 )/3 +2(u 1 w2 w3 + u 2 w3 w1 + u 3 w1 w2 ) + w1 w2 w3 f ∗ (u¯ 1 , u¯ 2 , δ) = 3u 1 u 2 + 2(0 + u 2 w1 + u 1 w2 )/3 + 2(0 + 0 + w1 w2 ) + 0 = 3u 1 u 2 + 2(u 2 w1 + u 1 w2 )/3 + 2w1 w2 ¯ u, ¯ δ) = 3u 2 + 4u/3 + 2 f ∗ (u, = F (1) (u)/3 By computing the derivative of F in the usual fashion, we see that the last step is true.

Then F(u) = 3u 3 + 2u 2 + 6u + 1 f ∗ (u¯ 1 , u¯ 2 , u¯ 3 ) = 3u 1 u 2 u 3 + 2(u 1 u 2 w3 + u 2 u 3 w1 + u 3 u 1 w2 )/3 +2(u 1 w2 w3 + u 2 w3 w1 + u 3 w1 w2 ) + w1 w2 w3 f ∗ (u¯ 1 , u¯ 2 , δ) = 3u 1 u 2 + 2(0 + u 2 w1 + u 1 w2 )/3 + 2(0 + 0 + w1 w2 ) + 0 = 3u 1 u 2 + 2(u 2 w1 + u 1 w2 )/3 + 2w1 w2 ¯ u, ¯ δ) = 3u 2 + 4u/3 + 2 f ∗ (u, = F (1) (u)/3 By computing the derivative of F in the usual fashion, we see that the last step is true. While the above is an awkward way to compute the derivative of a polynomial (especially if it is in monomial form), it is only intended as an example to show that the math really does work.

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